Question 1081072

let first integer be {{{x}}}, second one is {{{x+1}}}, and third one is {{{x+2}}}

{{{x+(x+1)+(x+2)=15}}} 

{{{x+x+1+x+2=15}}} 

{{{3x+3=15}}} 

{{{3x=15-3}}} 

{{{3x=12}}} 

{{{highlight(x=4)}}}->first integer 

second one is {{{x+1=4+1=highlight(5)}}}

and third one is {{{x+2=4+2=highlight(6)}}}


check their sum:

{{{x+(x+1)+(x+2)=15}}} 

{{{4+5+6=15}}} 

{{{15=15}}}