Question 1080998
2- Let the numbers be x,y,z
⇒{{{x+y+z=98}}}..i
x:y=2/3,y:z=5/8
 x=2y/3,z=8y/5
subtitute x and y in eqn i

{{{2y/3+y+8y/5=98}}}
 SOLVING I HAVE
 {{{10y+15y+24y=1470}}}
    49y=1470, y=30
∴ the second number is 30
check:x=20,y=30,z=48
      20+30+48=98