Question 1080928
{{{x=-y-5=-(y+5)}}}
{{{x^2=(-(y+5))^2=y^2+10y+25}}}
Substituting,
{{{y^2+10y+25+2y^2-4(-(y+5))+6y-5=0}}}
{{{y^2+10y+25+2y^2+4y+20+6y-5=0}}}
{{{3y^2+20y+40=0}}}
This equation has no real solutions.
So there is no solution to the system.
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Verified by the graph since there is no intersection.
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*[illustration 240.JPG].