Question 1080921
  Let the consequetive even integers = x, x+2, x+4, x+6.

  As per the condition, (x+x+4)*3 = 5(x+6)-28

  =  6x+12 = 5x+30-28.   Bringing the variable to left side,

  =  6x-5x = 30-28-12

  =  x = -10; x+2 = -8; x+4 = -6; x+6 = -4

  Therefore the nos. are -10, -8. -6, -4.  Answer.  

  I hope you understood this solution.  Always feel free to contact me at gsmani9@yahoo.com If you have any doubt. 

  God bless you.