Question 1080680
Use Cramer's rule,
{{{A=(matrix(3,3,
2,-1,1,
1,3,2,
3,-1,1))}}}
{{{abs(A)=-5}}}
.
.
{{{A[x]=(matrix(3,3,
0,-1,1,
16,3,2,
3,-1,1))}}}
{{{abs(A[x])=-15}}}
.
.
{{{A[y]=(matrix(3,3,
2,0,1,
1,16,2,
3,3,1))}}}
{{{abs(A[y])=-25}}}
.
.
{{{A[z]=(matrix(3,3,
2,-1,0,
1,3,16,
3,-1,3))}}}
{{{abs(A[z])=5}}}
.
.
.
.
{{{x=abs(A[x])/abs(A)=(-15)/(-5)=3}}}
{{{y=abs(A[y])/abs(A)=(-25)/(-5)=5}}}
{{{z=abs(A[z])/abs(A)=(5)/(-5)=-1}}}