Question 1080538
{{{P(X)=C(50,X)*(0.048)^X*(1-0.048)^(50-X)}}}
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*[illustration 4dr5.JPG].
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At least one, 
{{{P=1-P(0)}}}
{{{P=1-0.085}}}
{{{P=0.915}}}
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To get expected value,
{{{E[50]=sum(X*P(X),X=0,X=50)=2.4}}}
Round down to 2.
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In a box of 100,
{{{E[100]=2*2.4=4.8}}}
Round up to 5.