Question 1080569
Is that exponentiation? Use the caret "^".
x^2=1
{{{x^2=1}}}
{{{x^2-1=0}}}
{{{(x-1)(x+1)=0}}}
Two solutions,
{{{x-1=0}}}
{{{x=1}}}
and
{{{x+1=0}}}
{{{x=-1}}}