Question 1080374
if {{{X^2/a^2}}} - {{{Y^2/b^2}}} = 1 then Y is
multiply equation by a^2b^2, cancel the denominators
{{{x^2b^2}}} - {{{y^2a^2}}} = {{{a^2b^2}}} 
{{{x^2b^2}}} - {{{a^2b^2}}} = {{{y^2a^2}}}
divide by a^2
{{{y^2}}} = {{{((x^2b^2)-(a^2b^2))/a^2}}}
{{{y^2}}} = {{{(b^2(x^2-a^2))/a^2}}}
Find the square root of both sides
y = {{{sqrt(b^2(x^2-a^2)/a^2)}}}