Question 1080450
[(x - h)^2]/a^2 + [(y - k)^2]/b^2 = 1


If the major axis measures 50, then a = 25.

If the minor axis is 40, then b = 20.

Since we are centered at the origin, then h = 0 = k.


[(x - 0)^2]/(25)^2 + [(y - 0)]/(20)^2 = 1


(x^2)/625 + (y^2)/400 = 1