Question 1080423
Use {{{cos^2(theta)+sin^2(theta)=1}}}
{{{cos^2(theta)+49/100=1}}}
Solve for {{{cos(theta)}}}.
Due to the range given the solution will be negative.
Then,
{{{tan(theta)=sin(theta)/cos(theta)}}}
{{{cot(theta)=1/tan(theta)}}}
{{{sec(theta)=1/cos(theta)}}}
{{{csc(theta)=1/sin(theta)}}}