Question 1080333
...and one number is five more than the 2 numbers.
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{{{y=5+(x+y)}}}, ?
{{{y=5+x+y}}}
{{{0=5+x}}}
{{{x=-5}}}



The two numbers are x and y.
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sum of two numbers is twice their difference, 
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{{{x+y=2(y-x)}}}, assuming {{{x<y}}};
{{{x+y=-2x+2y}}}
{{{3x+y=2y}}}
{{{3x=y}}}



Putting the two results together,
{{{system(y=3x,x=-5)}}}

{{{y=3(-5)}}}
{{{y=-15}}}


-
{{{system(x=-5,and,y=-15)}}}