Question 1080287

Milk that has 3.25% milkfat is mixed with milk that has 1% milkfat. What volume of each is needed to obtain 60 litres of milk that has 3% milkfat? Express answer to the nearest tenth of a litre.

Note: Please include a "Let's statement(s)", and equations. Thank you :)
<pre>Let amount of 3.25% milkfat to be added, be T
Then amount of 1% milkfat to be added = 60 - T
We then get the following MIXTURE equation: .0325T + .01(60 - T) = .03(60)
.0325T + .6 - .01T = 1.8
.0325T - .01T = 1.8 - .6
.0225T = 1.2
T, or amount of 3.25% milkfat to be added = {{{highlight_green(matrix(1,4, 1.2/.0225, "=", 53.3, L))}}}
Amount of 1% milkfat to be added: {{{highlight_green(matrix(1,4, 60 - 53.3, "=", 6.7, L))}}}

If you want a system of equations, then let the amount of 3.25% and 1% to be added, be T, and S, respectively
Then the system is: {{{system(T + S = 60, .0325T + .01S = .03(60))}}}
Solve for T, and S to get the amount of 3.25% and 1%, respectively.
It's that easy. Nothing COMPLEX nor CONFUSING!