Question 1080288
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a coin collection consisting of nickels and quarters has a value of $4.50. The number of quarters is 4 less 
than twice the number of nickels. Find the number of nickel
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Let N be the number of nickels.
Then the number of quarters is (2N-4).

The "value" equation is 

5N + 25*(2N-4) = 450   (cents).

5N + 50N - 100 = 450  ====>  55N = 550  ====>  N = 10.
</pre>

Thanks to "MathTherapy" for pointing my error.