Question 95432
You can do this a couple ways. Let's solve this by substitution. First we take an equation and solve for one of the variables. In this case We're going to use your second equation {{{ 2x=y-4}}} and solve for y. We'll plug the y value then into the second equation.

{{{2x=y-4}}}
{{{-y=-2x-4}}}
{{{y=2x+4}}}

Now we'll substitute this for y in the first equation.
{{{8x+3y=26}}}
{{{8x+3(2x+4)=26}}}
{{{8x+6x+12=26}}}
{{{14x=14}}}
{{{x=1}}}

Now plug in the x value into either equation to get the y value.
{{{2x=y-4}}}
{{{2(1)=y-4}}}
{{{2+4=y}}}
{{{y=6}}}

This gives us the solution (1,6).

To check it just plug both values into either equation.
{{{8(1)+3(6)=26}}}
{{{8+18=26}}}
{{{26=26}}}