Question 1080175
So let's do this in pieces.
First the x distance.
From {{{x=-1}}} to {{{x=2}}} is {{{dx=2-(-1)=2+1=3}}}
Now the y-distance,
From {{{y=4}}} to {{{y=-2}}} is {{{dy=-2-4=-6}}}
So then start from (-1,4) and increase the distance three times, 
x first,
{{{-1+3*dx=-1+3(3)=-1+9=8}}}
Then y,
{{{4+3*dy=4+3(-6)=4-18=-14}}}
So then the terminal point is,
(8,-14)

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When I re-read the problem, I wasn't sure if the new line segment begins at (-1,4) (as I did above) or if it begins at (2,-2).
Here's the solution if it starts at (2,-2),
x first,
{{{2+3*dx=2+3(3)=2+9=11}}}
Then y,
{{{-2+3*dy=-2+3(-6)=-2-18=-20}}}
(11,-20)