Question 1080211
{{{10x^2+12x+4=4}}}

{{{10x^2+12x+4-4=0}}}


{{{10x^2+12x=0}}}

{{{x(10x+12)=0}}}

solutions for {{{x}}}:

{{{x=0}}}

and

{{{10x+12=0}}}=>{{{10x=-12}}}=>{{{x=-12/10}}}=>{{{x=-1.2}}}


{{{drawing( 600, 600, -10, 10, -10, 10, 
circle(0,4,.12),circle(-1.2,4,.12),
locate(0.9,4.5,p(0,4)),locate(-2.1,4.5,p(-1.2,4)),
 graph( 600, 600, -10, 10, -10, 10, 10x^2+12x+4,4)) }}}