Question 1079950

the perimeter of a rectangle is {{{P=2L+2W}}} where {{{L}}} is the length and {{{W}}} is the width

the perimeter of a rectangular area rug that is {{{L=(5+x)/2}}} feet long and {{{W=(2x-1)/3 }}}feet wide will be:

{{{P=cross(2)(5+x)/cross(2)+2(2x-1)/3}}}

{{{P=(5+x)+(4x-2)/3}}}

{{{P=(3(5+x)+(4x-2))/3}}}

{{{P=(15+3x+4x-2)/3}}}

{{{P=(7x+13)/3}}}