Question 1079943
{{{(16^(x+2))/64=(1/64)^(3x-2) }}}


{{{(16^(x+2))/64=(1^(3x-2))/(64^(3x-2) )}}}.........cross multiply


{{{(16^(x+2))(64^(3x-2) )=64(1^(3x-2))}}}


{{{((2^4)^(x+2))((2^6)^(3x-2) )=2^6(1^(3x-2))}}}...replace {{{1}}} as {{{2^0}}}


{{{((2^4)^(x+2))((2^6)^(3x-2) )=2^6((2^0)^(3x-2))}}}


{{{2^(4x+8)*2^(6(3x-2))=2^6*2^(0(3x-2))}}}


{{{2^(4x+8)*2^(18x-12) =2^6*2^0}}}


{{{2^(4x+8+18x-12) =2^6*1}}}


{{{2^(22x-4) =2^6}}}


{{{22x-4 =6}}}

{{{22x =6+4}}}

{{{22x =10}}}

{{{x =10/22}}}

{{{x =5/11}}}