Question 1079925


{{{(56*2^(5x))/3^(2x )= (7*4^x*3^x)/(27^x )}}}


{{{(56*2^(5x))(27^x )= 7*12^x*3^(2x )}}}


{{{(7*2^3*2^(5x))(27^x )= 7*12^x*3^(2x )}}}


{{{7 *2^(5x + 3) 27^x=7* 108^x}}}................cancel {{{7}}}, and since {{{108=4*27}}} we have


{{{2^(5x + 3)* 27^x=4^x*27^x }}}.............cancel {{{27^x}}}


{{{2^(5x + 3) =4^x}}}


{{{2^(5x + 3) =(2^2)^x}}}


{{{2^(5x + 3) =2^(2x)}}}........if base same, we have


{{{5x + 3 =2x}}}.............solve for {{{x}}}


{{{5x-2x=-3}}}


{{{3x=-3}}}


{{{x=-1}}}