Question 1079905
Table of values:

<table border=1><tr><th>x</th><th>y</th></tr><tr><td>-2</td><td>12</td></tr><tr><td>-1</td><td>7</td></tr><tr><td>0</td><td>4</td></tr><tr><td>1</td><td>3</td></tr><tr><td>2</td><td>4</td></tr></table>

which is the final answer


The work for each y value is shown below:


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If x = -2, then,


y = x^2-2x+4


y = (-2)^2-2*(-2)+4 ... <font color=blue>Plug in x = -2</font>


y = 4-2*(-2)+4


y = 4+4+4


y = 12


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If x = -1, then,


y = x^2-2x+4


y = (-1)^2-2*(-1)+4 ... <font color=blue>Plug in x = -1</font>


y = 1-2*(-1)+4


y = 1+2+4


y = 7


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If x = 0, then,


y = x^2-2x+4


y = (0)^2-2*(0)+4 ... <font color=blue>Plug in x = 0</font>


y = 0-2*(0)+4


y = 0-0+4


y = 4


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If x = 1, then,


y = x^2-2x+4


y = (1)^2-2*(1)+4 ... <font color=blue>Plug in x = 1</font>


y = 1-2*(1)+4


y = 1-2+4


y = 3


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If x = 2, then,


y = x^2-2x+4


y = (2)^2-2*(2)+4 ... <font color=blue>Plug in x = 2</font>


y = 4-2*(2)+4


y = 4-4+4


y = 4


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Extra Information:


The graph is shown below. Each point is on the same parabola.


<img src = "https://i.imgur.com/FIp6mWg.png">
Image generated using <a href = "https://www.geogebra.org/">GeoGebra</a> (free graphing software).


Each point is generated based on the (x,y) pairing. For instance, point A is (-2,12) because x = -2 leads to y = 12 which is shown in the first row of the table above.