Question 1079879

{{{cos(x) + tan(x)sin(x)}}} 


={{{cos(x) +(sin(x)/cos(x))sin(x)}}}


={{{cos(x) +(sin^2(x)/cos(x))}}}


={{{cos^2(x)/ cos(x)+sin^2(x)/cos(x) }}}


={{{(cos^2(x)+sin^2(x))/cos(x) }}}


={{{1/cos(x) }}}


={{{sec(x)}}}

so, your answer is a. {{{sec(x)}}}