Question 1079840
Mia walked n feet per minute and arrived at the clinic 10 minutes late. How fast should she have walked to have arrived on time?
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d = distance
d = n*t
t = d/n --> 10 minutes late
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t-10 = d/(n+s)  [s = increase in speed]
Solve for s
(t-10)*(n+s) = d
n(t-10) + s(t-10) = d
s = (d - nt + 10t)/(t-10)
s = 10t/(t-10)
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Walking {{{n + 10t/(t-10)}}} --> on time
= {{{(d - 10n + 10t)/(t-10)}}}