Question 1869
Are you sure it is 38x?


mutiply every term by 42, so that this cancels out the 6 and the 7 on the denominators

{{{42((3x+5)/7) + 42((4x-9)/6) = 42(38x)}}}
{{{6(3x+5) + 7(4x-9) = 42(38x)}}}
18x+30 + 28x-63 = 1596x
46x-33 = 1596x
-33 = 1550x

just re-writing this the other way gives 1550x = -33.

Hence x = -33/1550


cheers
Jon