Question 1079735
Pls help struggling to help ny daughter the question is If the square number of a positive is increased by 3 times the number, the result is 54.find the number 
<pre>Let the number be N
Then we get: {{{N^2 + 3N = 54}}}
{{{N^2 + 3N - 54 = 0}}} ------ Subtracting 54 from both sides
(N - 6)(N + 9) = 0 ------ Factoring TRINOMIAL on left
N - 6 = 0     OR      N + 9 = 0
N, or number = {{{highlight_green(6)}}}     OR       N = - 9 (ignore as this is NEGATIVE)