Question 1079677
reminder:

{{{x= r*cos(theta)}}}
{{{y= r*sin(theta)}}}

if

{{{2xy = 3}}}

{{{2*r*cos(theta)*r*sin(theta)= 3}}}


{{{r^2*cos(theta)*sin(theta)= 3/2}}}


{{{r^2= 3/(2cos(theta)*sin(theta))}}}


{{{r=sqrt( 3/(2cos(theta)*sin(theta)))}}}


so, your answer is C.