<PRE><B>Question 95142</B>
Assume you mean (x is not in the denominator)
{{{(5/6)x + (1/3) = (3/4)x - (1/2)}}}
:
Find a common multiple of all these denominators and multiply
12 is good choice:
{{{12(5/6)x + 12(1/3) = 12(3/4)x - 12(1/2)}}}
:
After some easy canceling we have:
2(5)x + 4(1) = 3(3)x - 6(1)
:
10x + 4 = 9x - 6
:
Some basic algebra operations:
10x - 9x = -6 - 4
x = -10
:
You can substitute -10 for x in the original equation and check for equality</PRE>