Question 1079630
The surface area of a right cone is 400.2 m^2. The radius of the cone is 6.0m. Determine the height of the cone to the nearest metre.
:
Surface Area of a cone: S.A. = {{{(pi*r*s) + (pi*r^2)}}} where:
r = the radius
s = the slant height
:
Find the s
{{{(pi*r*s) + (pi*6^2)}}} = 400.2
divide thru by pi
{{{(6*s) + (6^2)}}} = 127.3876
6s = 127.324 - 36
6s = 91.3876
s = 91.3876/6
s = 15.23 meter is the slant height
find the height using pythag; h^2 = 15.23^2 - 6^2 (h is the hypotenuse)
h = {{{sqrt(15.23^2 - 36^2)}}}
h = 14 meters is the height