Question 1079599
a=7 5th term=23
⇒T5th=7+4d=23
7+4d=23
4d=16
d=4
⇒common difference=4

15th term=a+14d

7+(14*4)=63

⇒15th term=63

Sum of 10th term
=n/2{2a+(n-1)d}
10/2{2*7+(9*4)}
=250