Question 1079591
{{{ ( a^3*(b^7)^-3 ) / ( a^3*b^(-3) ) }}}
If I just carry out the indicated operation in the numerator
following the rule: {{{ ( a^b )^c = a^(b*c) }}}
{{{ ( a^3*b^(-21) ) / ( a^3*b^(-3) ) }}}
Now I can cancel terms
{{{ ( a^3/a^3 )*( b^(-21) / b^(-3)) }}}
And, also, I can multiply top and bottom by
{{{ b^21 }}}
{{{ 1*( b^(-21)*b^21  / ( b^(-3)*b^21 )) }}}
{{{ b^0 / ( b^(-3)*b^21 ) }}}
{{{ 1 / b^( 21-3 ) }}}
{{{ 1 / b^18 }}}
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Check the math & get a 2nd opinion if needed