Question 1079502
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Express "t" from the first equation

t = x-3

and substitute it into the second equation y = t^2 -3t. You will get

y = {{{(x-3)^2 - 3(x-3)}}}.

Simplify further, and you will get

y = {{{x^2 - 6x + 9 - 3x + 9}}} = {{{x^2-9x + 18}}}.


Thus the answer is option D).
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