Question 1079530
If given,  x=t+3  &  y=t^2-3t , eliminate the parameter 
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t = x-3
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y = (x-3)^2 - 3(x-3)
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y = x^2 -6x + 9 - 3x + 9
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Ans: y = x^2 - 9x + 18
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Cheers,
Stan H.