Question 1079514
There are {{{ 10 }}} clubs, Ace  - 10,  excluding J, Q, and K of clubs
To the {{{ 10 }}} clubs, add J, Q, K of each of the 4 suits, which is
{{{ 12 }}} cards.
{{{ 10 + 12 = 22 }}}
The probability of choosing one of these is
{{{ 22/52 = 11/26 }}}