Question 1079391
<pre><b>
{{{drawing(400,2400/7,-5,9,-5,7, grid(1),

line(1,-3,-3,-1),line(-3,-1,3,5), locate(1,-3,"A(1,-3)"),
locate(-5,-1,"B(-3,-1)"), locate(3,5,"C(3,5)") )}}}

It's just a simple matter of counting blocks.
To get from B to A you go right 4 blocks and down 2 blocks.
like the red lines below:

{{{drawing(400,2400/7,-5,9,-5,7, grid(1),
red(line(-3,-1,1,-1),line(1,-1,1,-3),

line(-3+.01,-1+.01,1+.01,-1+.01),line(1+.01,-1+.01,1+.01,-3+.01),
line(-3-.01,-1-.01,1-.01,-1-.01),line(1-.01,-1-.01,1-.01,-3-.01)


),
line(1,-3,-3,-1),line(-3,-1,3,5), locate(1,-3,"A(1,-3)"),
locate(-5,-1,"B(-3,-1)"), locate(3,5,"C(3,5)") )}}}

So to get from C to D you do the same thing. Go right 4 blocks 
and down 2 blocks.  And so you end up at (7,3):

{{{drawing(400,2400/7,-5,9,-5,7, grid(1),
red(line(-3,-1,1,-1),line(1,-1,1,-3),
line(3,5,7,5),line(7,5,7,3),
line(3+.01,5+.01,7+.01,5+.01),line(7+.01,5+.01,7+.01,3+.01),
line(3-.01,5-.01,7-.01,5-.01),line(7-.01,5-.01,7-.01,3-.01),

line(-3+.01,-1+.01,1+.01,-1+.01),line(1+.01,-1+.01,1+.01,-3+.01),
line(-3-.01,-1-.01,1-.01,-1-.01),line(1-.01,-1-.01,1-.01,-3-.01)


),
line(1,-3,-3,-1),line(-3,-1,3,5), locate(1,-3,"A(1,-3)"),
locate(-5,-1,"B(-3,-1)"), locate(3,5,"C(3,5)") )}}}

Then you erase the red lines, and draw in the rest of the
parallelogram:

{{{drawing(400,2400/7,-5,9,-5,7, grid(1),
line(3,5,7,3), line(1,-3,7,3),locate(7,3,"D(7,3)"),
line(1,-3,-3,-1),line(-3,-1,3,5), locate(1,-3,"A(1,-3)"),
locate(-5,-1,"B(-3,-1)"), locate(3,5,"C(3,5)") )}}}

Answer: (7,3)

Edwin</pre>