Question 1079223
{{{cos(theta)^2+sin(theta)^2=1}}}

{{{(3/5)^2+sin(theta)^2=1}}}
{{{sin(theta)^2=1-9/25}}}
{{{sin(theta)=sqrt(16/25)}}}
Since it's Q1,
{{{sin(theta)=4/5}}}
So then,
{{{tan(theta)=(4/5)/(3/5)=(4/5)(5/3)}}}
{{{cot(theta)=1/tan(theta)}}}
{{{sec(theta)=1/cos(theta)=5/3}}}
{{{csc(theta)=1/sin(theta)=5/4}}}