Question 1079200
{{{log((3^(x-1)))=log((100^x)))}}}

{{{(x-1)log((3))=x*log((100))}}}

{{{x*log((3))-log((3))=x*log((100))}}}
{{{-log((3))=x*log((100))-x*log((3))}}}


{{{-log((3))=x(log((100))-log((3)))}}}


{{{x=(-log((3)))/(log((100))-log((3)))}}}


{{{x=(-0.4771213)/(2-0.4771213)}}}


{{{x=-0.3133}}}