Question 1079156
-16t^2+16t+32=0 when it hits the ground.
a) 0 is the value of s
b)-16t^2+16t+32=0
c)-16(t^2-t-2)=0 and (t-2)(t+1)=0, so t=2 or -1
d) only the t=2 is a solution since time has to be positive.
e) -16t^2+16t=32=32; -16t^2+16t=0, t=0, t=1, only 1 makes sense.
(the building is 32 feet tall.)
{{{graph(300,300,-5,5,-10,40,-16x^2+16x+32)}}}