Question 95237
Draw the picture of the three unequal squares.
Label the side of the smallest as "x"
Label the side of the largest as "x+3"
Label the side of the other as "x+1"
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The area of a square is the square of its side.
EQUATION:
x^2 + (x+1)^2 + (x+3)^2 =  38 km^2
x^2 + x^2+3x+1 + x^2+6x+9= 38
3x^2 + 9x + 10 = 38
3x^2+9x-28 = 0
x = [-9+- sqrt(81-4*3*-28)]/6

x = [-9 +-sqrt(417)]/6
x = [-9+-20.4206]/6
x = [11.4206]/6
x = 1.9034 km; Area of this field = 3.623..km^2
x+1 = 2.903429 km.; Area of this field = 8.4299..km^2
x+3 = 4.903429 km. ; 24.0436... km^2
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Adding these you will not get 38 km^2.  I think area
is lost in the restricted decimals but you should
check the arithmetic of the problem.
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Cheers,
Stan H.