Question 1079056
x^2-2x+3
{{{graph(300,300,-10,10,-10,10,x^2-2x+3)}}} 
-x^2+2x-2
{{{graph(300,300,-10,10,-10,10,-x^2+2x-2)}}}
parallel lines have the same slope
point slope formula where y-y1=m(x-x1), m slope, (x1,y1) a point. Watch the signs.
y+1=(3/2)(x-4) and y=(3/2)x-7
{{{graph(300,300,-10,10,-10,10,(3/2)x-4,(3/2)x-7)}}}
Perpendicular lines have a negative reciprocal slope
slope of the given line is 5/2, so line perpendicular has a slope of -2/5
y-2=(-2/5)(x+4)
y=(-2/5)x+(2/5)
{{{graph(300,300,-10,10,-10,10,2.5x-0.5,(-2/5)x+(2/5))}}}