Question 1078981

if   the length is {{{L}}}, width{{{W}}} , and height {{{h}}}, the volume of the larger prism is

{{{V=L*W*h}}}

 each cut in half, we have {{{L/2}}}, {{{W/2}}}, and {{{h/2}}}, so the volume of the smaler prism is {{{V[1]=(L/2)*(W/2)*(h/2)}}}

{{{V[1]=(L*W*h)/(2*2*2)}}}

than {{{V/V[1]=(L*W*h)/(L*W*h)/8}}}
{{{V/V[1]=8(cross(L*W*h)1)/(cross(L*W*h)1)}}}
{{{V/V[1]=8/1}}}

{{{V*1=8*V[1]}}}
{{{V=8V[1]}}}
 the ratio of the volume of the smaller prism to the volume of the larger prism is {{{1}}}to {{{8}}}