<PRE><B>Question 1078950</B>
There are six items total. You are to select three of them at random, putting them in a specific order. In other words, order matters. It is a permutation question. How many different arrangements of 3 can be made this way? 
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# of groups of 3 = 6C3 = (6*5*4)/(1*2*3) = 20
# of arrangements of the set you pick 3! = 6
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Total # of arrangements possible:: 20*6 = 120
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Cheers,
Stan H.
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