Question 1078955
Let n and 20-n be the amounts of 25% o.j. and 5% o.j., respectively. Then
.25n+0.05(20-n)=0.21(20)
0.2n+1=4.2
0.2n=3.2
n=16
You need 16L of 25% juice, and 4L of 5% juice. &#9786;&#9786;&#9786;&#9786;