Question 1078905
{{{f(x)=3x^2}}} 

find {{{f^-1(x)}}} : recall that {{{f(x)=y}}}

{{{y=3x^2}}}.....switch {{{x}}} and {{{y}}} 

{{{x=3y^2}}}

{{{x/3=y^2}}}

{{{y=sqrt(x/3)}}}

{{{y=sqrt(x)/sqrt(3)}}}

so, your inverse is {{{f^-1(x)=sqrt(x)/sqrt(3)}}}

domain:

 should exclude {{{x=0}}} value and domain is all non-negative real numbers

{ {{{x}}} element of {{{R}}}: {{{x>=0}}} }