Question 1078771
Log10x+log4x=2 find value of x
-----
log[10x*4x] = 2
log[40x^2] = 2
-----
40x^2 = 10^2
x^2 = 100/40
x^2 = 2.5
x = +/-sqrt(2.5)
----------------
Cheers,
Stan H.
-----------