Question 1078683
We have Tn = a*r^(n-1) where Tn is nth tern, a = 1st term and r = common ratio.
Here 10 = a*r^(6-1)= ar^5            ----(1)
Also 0.1 = a*r^(16-1) = a r^15       ----- (2)
(1)/(2) gives r= 0.01^0.1
and, hence, a = 10/(0.01)^0.5
Hence, 11th term = T11 = ar^10= [10/0.01^0.5]*0.01
= 10(0.01)^0.5
= 1