Question 1078546
Find the point of intersection.
{{{x=-3y-7}}}
Substitute into the second equation,
{{{3(-3y-7)-2y-12=0}}}
{{{-9y-21-2y-12=0}}}
{{{-11y-33=0}}}
{{{-11y=33}}}
{{{y=-3}}}
So,
{{{x=-3(-3)-7}}}
{{{x=9-7}}}
{{{x=2}}}
So then,
{{{(x-2)^2+(y-(-3))^2=R^2}}}
{{{(x-2)^2+(y+3)^2=R^2}}}
Using the point,
{{{(-1-2)^2+(1+3)^2=R^2}}}
{{{(-3)^2+4^2=R^2}}}
{{{R^2=9+16}}}
{{{R^2=25}}}
Finally,
{{{(x-2)^2+(y+3)^2=25}}}