Question 1078425
N=Noe^kt. Let t=number of months.
N/No=2=e^k(18)
ln 2=ln (e^18k)=18k
k=ln2/18=0.03850
t now equals 24 with the new population of 10,000
N=Noe^(24k); 
N=10000^(24*0.0385)=10000*e^0.924
N=25,193.
This is consistent with doubling and then increasing more in the 6 months after the doubling.