Question 1078374
So {{{9^2=81}}}, {{{a=9}}},
{{{x=80}}} and you're looking for {{{sqrt(80)}}}
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So then,
{{{y[1]=(1/2)(9+80/9)=(1/2)(81/9+80/9)=(1/2)(161/9)=161/18}}}
{{{y[2]=(1/2)(161/18+80/(161/18))=(1/2)(161/18+1440/161)=(1/2)(51841/2898)=51841/5796}}}
There's a start.
Work through the rest of the problem.