<PRE><B>Question 1078225</B>
 A die is rolled twice. What is the probability of getting either a multiple of 3 on the first roll or a total of 8 for both rolls? 
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P(mult of 3) = [2+4+4+1]/36
P(sum of 8) = 5/36
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P(mult of 3 or sum of 8) = (11+5)/36 = 16/36
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Cheers,
Stan H.
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