<PRE><B>Question 1078199</B>
A triangle has sides of length 5 ft, 9 ft, and 13 ft.

What is the measure of the angle opposite the side that is 9 ft long?
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Use the Cosine Law
Call it angle B
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9^2 = 5^2 + 13^2 - 2*5*13*cos(B)
130*cos(B) = -113
cos(B) = ~ -0.86923
B =~ 150º
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