Question 1078191
{{{M=D+16}}}
and
{{{D=C-13}}}
{{{C=D+13}}}
and
{{{M+D+C=62}}}
Substituting,
{{{(D+16)+D+(D+13)=62}}}
{{{3D+29=62}}}
{{{3D=33}}}
Solve for D then work backwards to solve for M and C.